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Electrostatic Potential and Capacitance · Question 41

JEE Main 2025 (Online) 28th January Morning ShiftMCQEasy📈 Topic in 13% papers+4−1
1

Two capacitors C1 and C2 are connected in parallel to a battery. Charge-time graph is shown below for the two capacitors. The energy stored with them are U1 and U2, respectively. Which of the given statements is true? [figure]

  1. C2 > C1, U2 > U1
  2. C1 > C2, U1 > U2
  3. C2 > C1, U2 < U1
  4. C1 > C2, U1 < U2

Answer

(1) C2 > C1, U2 > U1

Solution

In parallel, both capacitors are finally charged to the same voltage V (battery emf).

From the graph, the final (saturation) charge of C2 is greater: Q2 > Q1

Q = CV with the same V C2 > C1

Energy: U = 12QV with the same V U2 > U1

Answer: (1)

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2

A particle of mass 'm' and charge 'q' is fastened to one end 'A' of a massless string having equilibrium length l, whose other end is fixed at point 'O'. The whole system is placed on a frictionless horizontal plane and is initially at rest. If uniform electric field is switched on along the direction as shown in figure, then the speed of the particle when it crosses the x-axis is [figure]

  1. qEl2m
  2. qEl4m
  3. qElm
  4. 2qElm
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3

A parallel plate capacitor of capacitance 1 μF is charged to a potential difference of 20 V. The distance between plates is 1 μm. The energy density between plates of capacitor is :

  1. 1.8 103 J/m3
  2. 2 102 J/m3
  3. 2 10-4 J/m3
  4. 1.8 105 J/m3
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4

An electric dipole of dipole moment 6 10-6 C m is placed in uniform electric field of magnitude 106 V/m. Initially, the dipole moment is parallel to electric field. The work that needs to be done on the dipole to make its dipole moment opposite to the field, will be J.

JEE Main 2025 (Online) 28th January Evening Shift

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