From the magnetic behaviour of [NiCl4]2- (paramagnetic) and [Ni(CO)4] (diamagnetic), choose the correct geometry and oxidation state.
- [NiCl4]2- : Ni(0), tetrahedral [Ni(CO)4] : Ni(0), square planar
- [NiCl4]2- : NiII, tetrahedral [Ni(CO)4] : Ni(0), tetrahedral
- [NiCl4]2- : NiII, tetrahedral [Ni(CO)4] : NiII, square planar
- [NiCl4]2- : NiII, square planar [Ni(CO)4] : Ni(0), square planar
Answer
(2) [NiCl4]2- : NiII, tetrahedral [Ni(CO)4] : Ni(0), tetrahedral
Solution
[NiCl4]2-: Ni2+, 3d8; weak-field Cl- no pairing
[figure]
sp3, tetrahedral, 2 unpaired electrons (paramagnetic)
[Ni(CO)4]: Ni(0), 3d10 (strong-field CO pairs the 4s electrons into 3d)
[figure]
sp3, tetrahedral, diamagnetic
Answer: (2)