The axis of a parabola is the line y=x and its vertex and focus are in the first quadrant at distances 2 and 2 2 units from the origin, respectively. If the point (1, k) lies on the parabola, then a possible value of k is :
- 8
- 3
- 9
- 4
Answer
(3) 9
Solution
Points of y=x in the first quadrant at distance 2 and 2 2 from O:
Vertex V=(1, 1), focus S=(2, 2)
the directrix is perpendicular to y=x and as far from V as S is, i.e. it passes through (0, 0): x+y=0
Parabola: PS2=(distance of P from directrix)2
(x-2)2+(y-2)2= (x+y)22
Put (1, k): 1+(k-2)2= (1+k)22
2+2k2-8k+8=k2+2k+1
k2-10k+9=0 (k-1)(k-9)=0
k=1 or k=9; from the options, k=9
Answer: (3)