The displacement of a particle executing simple harmonic motion is given by y = A0 + A t + B t. Then the amplitude of its oscillation is given by :
- A2 + B2
- A + B
- A + A2 + B2
- A02 + (A + B)2
Answer
(1) A2 + B2
Solution
The constant term A0 only shifts the mean position; it does not change the amplitude.
y - A0 = A t + B t
Two SHMs of the same ω with a phase difference of 90 combine as:
⇒ A t + B t = R ( t + ), where R = A2 + B2
∴ Amplitude = A2 + B2
Answer: (1)