A pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is 20 m s-2 at a distance of 5 m from the mean position. The time period of oscillation is
- 2 s
- s
- 2 s
- 1 s
Answer
(2) s
Solution
In SHM: |a| = 2 x
⇒ 20 = 2 5 ⇒ 2 = 4 ⇒ = 2 rad s-1
Time period: T = 2 = 2 2
∴ T = s
Answer: (2)