A cup of coffee cools from 90 to 80 in t minutes when the room temperature is 20 . The time taken by the similar cup of coffee to cool from 80 to 60 at the same room temperature is:
- 135t
- 1013t
- 513t
- 1310t
Answer
(1) 135t
Solution
Newton's law of cooling (average form): T t=k (Tavg-T0 )
Case 1: 10t=k(85-20)=65k
Case 2: 20t'=k(70-20)=50k
Divide: t'2t= 6550
∴ t'= 135t
Answer: (1)