A first row transition metal in its +2 oxidation state has a spin-only magnetic moment value of 3.86 BM. The atomic number of the metal is
- 22
- 23
- 26
- 25
Answer
(2) 23
Solution
= n(n+2) BM ⇒ 3 5 = 15 = 3.87 3.86 ⇒ n = 3
M2+ with 3 unpaired electrons ⇒ 3d3 ⇒ V2+
∵ Ti2+ 3d2 (n = 2), Mn2+ 3d5 (n = 5), Fe2+ 3d6 (n = 4)
∴ Z = 23
Answer: (2)