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Kinetic Theory

JEE Main 2024 (Online) 29th January Evening ShiftMCQEasy📈 Topic in 17% papers+4−1
Ques. 1JEE Main 2024, 29 January (Evening Shift)

The temperature of a gas having 2.0 1025 molecules per cubic meter at 1.38 atm (Given, k=1.38 10-23 J K-1) is :

  1. 500 K
  2. 300 K
  3. 200 K
  4. 100 K

Answer

(1) 500 K

Solution

PV=NkT P=nkT, where n= NV = molecules per unit volume

T= Pnk= 1.38 1.01 1052.0 1025 1.38 10-23

= 1.01 105200 505 K 500 K

1 atm=1.01 105 Pa

Answer: (1)

Keep practising — Kinetic Theory

Ques. 2JEE Main 2024, 29 January (Evening Shift)

N moles of a polyatomic gas (f=6) must be mixed with two moles of a monoatomic gas so that the mixture behaves as a diatomic gas. The value of N is :

  1. 6
  2. 2
  3. 4
  4. 3
Ques. 3JEE Main 2024, 27 January (Morning Shift)

The average kinetic energy of a monatomic molecule is 0.414 eV at temperature : (Use KB = 1.38 10-23 J/K)

  1. 3000 K
  2. 3200 K
  3. 1600 K
  4. 1500 K
Ques. 4JEE Main 2024, 27 January (Evening Shift)

The total kinetic energy of 1 mole of oxygen at 27 is : [Use universal gas constant (R)=8.31 J/mole K]

  1. 6232.5 J
  2. 5670.5 J
  3. 6845.5 J
  4. 5942.0 J

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