Ques. 1JEE Main 2024, 29 January (Evening Shift)
The temperature of a gas having 2.0 1025 molecules per cubic meter at 1.38 atm (Given, k=1.38 10-23 J K-1) is :
- 500 K
- 300 K
- 200 K
- 100 K
Answer
(1) 500 K
Solution
PV=NkT P=nkT, where n= NV = molecules per unit volume
T= Pnk= 1.38 1.01 1052.0 1025 1.38 10-23
= 1.01 105200 505 K 500 K
1 atm=1.01 105 Pa
Answer: (1)