The total kinetic energy of 1 mole of oxygen at 27 is : [Use universal gas constant (R)=8.31 J/mole K]
- 6232.5 J
- 5670.5 J
- 6845.5 J
- 5942.0 J
Answer
(1) 6232.5 J
Solution
O2 is diatomic: f=5 (3 translational + 2 rotational).
Each degree of freedom carries 12RT per mole (equipartition).
E= f2nRT= 52 1 8.31 300
=6232.5 J
Answer: (1)