Given below are two statements: In the light of the above statements, choose the most appropriate answer from the options given below:
- Statement I is correct but Statement II is incorrect
- Statement I is incorrect but Statement II is correct
- Both Statement I and Statement II are correct
- Both Statement I and Statement II are incorrect
Answer
(2) Statement I is incorrect but Statement II is correct
Solution
Statement I: Hydroboration of propene is anti-Markovnikov; boron adds to the terminal carbon:
3CH3-CH=CH2 + 12B2H6 (CH3-CH2-CH2)3B
The product is tripropylborane, not ((CH3)2-CH)3B. Statement I is incorrect.
Statement II: On oxidation with H2O2/NaOH, each B–C bond is replaced by C–OH with the OH on the same carbon that carried boron:
((CH3)2CH)3B H2O2, NaOH 3(CH3)2CH-OH (propan-2-ol)
Statement II is correct.
Answer: (2)