The co-ordinates of a particle moving in x-y plane are given by : x=2+4t, y=3t+8t2. The motion of the particle is :
- uniform motion along a straight line.
- non-uniformly accelerated.
- uniformly accelerated having motion along a straight line.
- uniformly accelerated having motion along a parabolic path.
Answer
(4) uniformly accelerated having motion along a parabolic path.
Solution
vx= dxdt=4, vy= dydt=3+16t
ax=0, ay=16 m/s2 = constant uniformly accelerated
Path: t= x-24 y= 3(x-2)4+ (x-2)22 (quadratic in x)
a is not along the initial u=4 i+3 j, the path is a parabola
Answer: (4)