The maximum height reached by a projectile is 64 m. If the initial velocity is halved, the new maximum height of the projectile is m.
Answer
16
Solution
H = u2 2 2g
is unchanged H u2
H' = 64 ( 12 )2 = 16 m
Answer: 16
The maximum height reached by a projectile is 64 m. If the initial velocity is halved, the new maximum height of the projectile is m.
16
H = u2 2 2g
is unchanged H u2
H' = 64 ( 12 )2 = 16 m
Answer: 16
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