Let H1: x2a2- y2b2=1 and H2:- x2A2+ y2B2=1 be two hyperbolas having length of latus rectums 15 2 and 12 5 respectively. Let their eccentricities be e1= 52 and e2 respectively. If the product of the lengths of their transverse axes is 100 10, then 25e22 is equal to .
Answer
55
Solution
H1: e12=1+ b2a2= 52 b2= 32a2
Latus rectum 2b2a=3a=15 2 a=5 2, transverse axis 2a=10 2
H2 (transverse axis 2B along y): 10 2 2B=100 10 B=5 5
Latus rectum 2A2B=12 5 A2=150
e22=1+ A2B2=1+ 150125= 115
25e22=55
Answer: 55