Let a circle pass through the origin and its centre be the point of intersection of two mutually perpendicular lines x+(k-1)y+3=0 and 2x+k2y-4=0. If the line x-y+2=0 intersects the circle at the points A and B, then (AB)2 is equal to :
- 10
- 27
- 18
- 34
Answer
(3) 18
Solution
The lines are perpendicular: 1 2+(k-1)k2=0
k3-k2+2=0 (k+1)(k2-2k+2)=0
k2-2k+2=(k-1)2+1>0, so k=-1
With k=-1 the lines are x-2y+3=0 and 2x+y-4=0
Solving: centre C=(1, 2)
Circle passes through O r2=12+22=5
Distance of C from x-y+2=0: d= |1-2+2| 2= 1 2
(AB)2=4 (r2-d2 )=4 (5- 12 )=18
Answer: (3)