Ques. 1JEE Main 2024, 29 January (Evening Shift)
If e a, e b, e c are in an A.P. and e a- e 2b, e 2b- e 3c, e 3c- e a are also in an A.P., then a:b:c is equal to
- 6:3:2
- 9:6:4
- 25:10:4
- 16:4:1
Answer
(2) 9:6:4
Solution
e a, e b, e c in A.P. b2=ac … (i)
Second A.P.: e a2b, e 2b3c, e 3ca
( 2b3c )2= a2b 3ca= 3c2b
( 2b3c )3=1 c= 2b3
(i) b2=a 2b3 a= 3b2
a:b:c= 32:1: 23=9:6:4
Answer: (2)