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Complex Numbers and Quadratic Equations

JEE Main 2024 (Online) 29th January Morning ShiftNumericalMedium📈 Topic in 34% papers+4
Ques. 1JEE Main 2024, 29 January (Morning Shift)

Let , be the roots of the equation x2-x+2=0 with Im( )>Im( ). Then 6+ 4+ 4-5 2 is equal to .

Answer

13

Solution

∵ α, β are roots: 2= -2, 2= -2, + =1

4=( -2)2= 2-4 +4=-3 +2 (similarly 4=-3 +2)

6= 4 2=(-3 +2)( -2)=-3 2+8 -4=5 +2

Expression =(5 +2)+(-3 +2)+(-3 +2)-5( -2)

=-3( + )+16=-3+16=13

Answer: 13

Keep practising — Complex Numbers and Quadratic Equations

Ques. 2JEE Main 2024, 29 January (Evening Shift)

Let r and respectively be the modulus and amplitude of the complex number z=2-i (2 5 8 ), then (r, ) is equal to

  1. (2 11 8, 11 8 )
  2. (2 3 8, 3 8 )
  3. (2 5 8, 3 8 )
  4. (2 3 8, 5 8 )
Ques. 3JEE Main 2024, 29 January (Evening Shift)

Let , be the roots of the equation x2- 6x+3=0 such that Im( )>Im( ). Let a, b be integers not divisible by 3 and n be a natural number such that 99 + 98=3n(a+ib), i= -1. Then n+a+b is equal to .

Ques. 4JEE Main 2024, 27 January (Morning Shift)

If S=\z :|z-i|=|z+i|=|z-1|\, then, n(S) is :

  1. 1
  2. 2
  3. 3
  4. 0
Ques. 5JEE Main 2024, 27 January (Morning Shift)

If satisfies the equation x2+x+1=0 and (1+ )7=A+B +C 2, A, B, C 0, then 5(3A-2B-C) is equal to .

Ques. 6JEE Main 2024, 27 January (Evening Shift)

If , are the roots of the equation, x2-x-1=0 and Sn=2023 n+2024 n, then :

  1. 2S12=S11+S10
  2. S12=S11+S10
  3. S11=S10+S12
  4. 2S11=S12+S10
Ques. 7JEE Main 2024, 27 January (Evening Shift)

Let the complex numbers and 1 lie on the circles |z-z0 |2=4 and |z-z0 |2=16 respectively, where z0=1+i. Then, the value of 100| |2 is .

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