A long solenoid carrying a current produces a magnetic field B along its axis. If the current is doubled and the number of turns per cm is halved, the new value of the magnetic field is
- B/2
- B
- 2B
- 4B
Answer
(2) B
Solution
As per NCERT, field inside a long solenoid: B = 0 nI
⇒ B' = 0 ( n2 )(2I) = 0 nI
∴ B' = B
Answer: (2)