The value of net resistance of the network as shown in the given figure is : [figure]
- ( 3011 )
- 6
- ( 52 )
- ( 154 )
Answer
(2) 6
Solution
-6 V>-8 V, current flows from left to right.
Diode with 10 Ω: arrow points left → right forward biased conducts (ideal: zero resistance).
Diode with 5 Ω: arrow points right → left reverse biased no current, 5 Ω branch is open.
Equivalent circuit:
[figure]
Rnet= 15 1015+10= 15025=6
Answer: (2)