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Sequences and Series · Question 3

JEE Main 2026 (Online) 6th April Morning ShiftMCQMedium📈 Topic in 42% papers+4−1
1

The sum of the first ten terms of an A.P. is 160 and the sum of the first two terms of a G.P. is 8. If the first term of the A.P. is equal to the common ratio of the G.P. and the first term of the G.P. is equal to common difference of the A.P., then the sum of all possible values of the first term of the G.P. is :

  1. 349
  2. 3413
  3. 329
  4. 3213

Answer

(1) 349

Solution

Let the G.P. have first term g and common ratio r

A.P. : first term r, common difference g

A.P. : S10= 102 [2r+9g ]=160 2r+9g=32 … (i)

G.P. : g+gr=8 g(1+r)=8 … (ii)

From (i) : r= 32-9g2 1+r= 34-9g2

Put in (ii) : g 34-9g2=8

9g2-34g+16=0

Discriminant =342-4 9 16=1156-576=580>0

two real values of g, both non-zero (product = 169)

Sum of all possible values of g= 349

Answer: (1)

JEE Main 2026 (Online) 6th April Morning Shift

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2

For the functions f( )= 2 + 2 , and g( )= 2 + 2 , > >0, let 0< < 2 f( )= 0< < g( ). If the first term of a G.P. is ( 2 ), its common ratio is ( 2 ) and the sum of its first 10 terms is mn, (m, n)=1, then m+n is equal to .

JEE Main 2026 (Online) 6th April Morning Shift
3

Consider the quadratic equation (n2-2n+2 )x2-3x+ (n2-2n+2 )2=0, n R. Let be the minimum value of the product of its roots and be the maximum value of the sum of its roots. Then the sum of the first six terms of the G.P., whose first term is and the common ratio is , is :

  1. 6137
  2. 12181
  3. 364243
  4. 1093729
JEE Main 2026 (Online) 6th April Evening Shift
4

The sum 1+ 12 (12+22 )+ 13 (12+22+32 )+ upto 10 terms is equal to :

  1. 130
  2. 155
  3. 3152
  4. 3252
JEE Main 2026 (Online) 6th April Evening Shift
5

Let the sum of the first n terms of an A.P. be 3n2+5n. Then the sum of squares of the first 10 terms of the A.P. is:

  1. 10220
  2. 12860
  3. 15220
  4. 19780
JEE Main 2026 (Online) 5th April Morning Shift
6

n=110 ( 528n(n+1)(n+2) ) is equal to:

  1. 65
  2. 130
  3. 220
  4. 440
JEE Main 2026 (Online) 5th April Morning Shift
7

If the sum of the first 10 terms of the series 11+14 4+ 21+24 4 + 31+34 4+ 41+44 4+ is mn, (m, n)=1, then m+n is equal to :

  1. 256
  2. 264
  3. 276
  4. 284
JEE Main 2026 (Online) 5th April Evening Shift
8

Let A1, A2, A3, , A39 be 39 arithmetic means between the numbers 59 and 159. Then the mean of A25, A28, A31 and A36 is equal to :

  1. 129
  2. 136
  3. 131.50
  4. 134
JEE Main 2026 (Online) 5th April Evening Shift
9

The first term of an A.P. of 30 non-negative terms is 103. If the sum of this A.P. is the cube of its last term, then its common difference is:

  1. 587
  2. 2583
  3. 1529
  4. 529
JEE Main 2026 (Online) 4th April Morning Shift
10

Let = 14+ 18+ 116+ and = 13+ 19+ 127+ . Then the value of (0.2) 5( )+(0.04) 5( ) is equal to :

  1. 4
  2. 5
  3. 8
  4. 25
JEE Main 2026 (Online) 4th April Evening Shift
11

Let A be the set of first 101 terms of an A.P., whose first term is 1 and the common difference is 5 and let B be the set of first 71 terms of an A.P., whose first term is 9 and the common difference is 7. Then the number of elements in A B, which are divisible by 3, is :

  1. 4
  2. 5
  3. 6
  4. 7
JEE Main 2026 (Online) 2nd April Morning Shift

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