A biconvex lens has radii of curvature, 20 cm each. If the refractive index of the material of the lens is 1.5, the power of the lens is
- +2 D
- +20 D
- +5 D
- Infinity
Answer
(3) +5 D
Solution
Lens maker's formula: 1f = ( - 1) ( 1R1 - 1R2 )
R1 = +20 cm, R2 = -20 cm
1f = (1.5 - 1) ( 120 + 120 ) = 120 cm-1
f = 20 cm = 0.2 m
P = 1f = 10.2 = +5 D
Answer: (3)