Ques. 1JEE Main 2024, 27 January (Evening Shift)
If y=y(x) is the solution curve of the differential equation (x2-4 )dy- (y2-3y )dx=0, x>2, y(4)= 32 and the slope of the curve is never zero, then the value of y(10) equals :
- 31+(8)1/4
- 31-(8)1/4
- 31-2 2
- 31+2 2
Answer
(1) 31+(8)1/4
Solution
dyy(y-3)= dxx2-4
13 | y-3y |= 14 | x-2x+2 |+C
x=4, y= 32: 0= 14 13+C C= 14 3
x=10: 13 | y-3y |= 14 (3 812 )= 14 2
| y-3y |=23/4=(8)1/4
∵ slope never zero, y never reaches 0 or 3; y(4)= 32 0<y<3
3-yy=(8)1/4
y(10)= 31+(8)1/4
Answer: (1)