Resistances n, each of r ohm, when connected in parallel give an equivalent resistance of R ohm. If these resistances were connected in series, the combination would have a resistance in ohms, equal to
- n2R
- R/n2
- R/n
- nR
Answer
(1) n2R
Solution
In parallel: R = rn r = nR
In series: Rs = nr
Rs = n(nR) = n2R
Answer: (1)