The truth table corresponding to the circuit given below is: [figure]
- arrayccc A & B & C \ 0 & 0 & 0 \ 0 & 1 & 0 \ 1 & 0 & 1 \ 1 & 1 & 1 array
- arrayccc A & B & C \ 0 & 0 & 1 \ 1 & 0 & 0 \ 0 & 1 & 0 \ 1 & 1 & 0 array
- arrayccc A & B & C \ 0 & 0 & 1 \ 0 & 1 & 0 \ 1 & 0 & 0 \ 1 & 1 & 0 array
- arrayccc A & B & C \ 0 & 0 & 0 \ 1 & 0 & 0 \ 0 & 1 & 0 \ 1 & 1 & 1 array
Answer
(1) arrayccc A & B & C \ 0 & 0 & 0 \ 0 & 1 & 0 \ 1 & 0 & 1 \ 1 & 1 & 1 array
Solution
Output of the OR gate: Y1 = A + B
The AND gate receives A (the wire from A over the top) and Y1:
C = A (A + B) = A A + A B = A + A B = A(1 + B) = A
C is the same as A:
A = 0, B = 0 C = 0; A = 0, B = 1 C = 0
A = 1, B = 0 C = 1; A = 1, B = 1 C = 1
This is the table in option (1).
Answer: (1)