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Semiconductor Electronics · Question 29

JEE Main 2025 (Online) 2nd April Morning ShiftMCQEasy📈 Topic in 23% papers+4−1
1

A zener diode with 5 V zener voltage is used to regulate an unregulated dc voltage input of 25 V. For a 400 resistor connected in series, the zener current is found to be 4 times load current. The load current (IL) and load resistance (RL) are :

  1. IL = 0.02 mA; RL = 250
  2. IL = 10 A; RL = 0.5
  3. IL = 10 mA; RL = 500
  4. IL = 20 mA; RL = 250

Answer

(3) IL = 10 mA; RL = 500

Solution

Current through series resistor: I = 25 - 5400 = 0.05 A = 50 mA

I = IZ + IL = 4IL + IL = 5IL

IL = 10 mA

Load is in parallel with the zener VL = 5 V

RL = 510 10-3 = 500

Answer: (3)

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2

In the digital circuit shown in the figure, for the given inputs the P and Q values are : [figure]

  1. P = 0, Q = 1
  2. P = 1, Q = 0
  3. P = 0, Q = 0
  4. P = 1, Q = 1
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3

[figure] For the circuit shown above, equivalent GATE is :

  1. NOT gate
  2. NAND gate
  3. AND gate
  4. OR gate
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4

Which of the following circuits has the same output as that of the given circuit? [figure]

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
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5

[figure] In the circuit shown here, assuming threshold voltage of diode is negligibly small, then voltage VAB is correctly represented by:

  1. [figure]
  2. [figure]
  3. VAB would be zero at all times.
  4. [figure]
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