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JEE Main 2024 (Online) 29th January Evening ShiftNumericalMedium📈 Topic in 14% papers+4
Ques. 1JEE Main 2024, 29 January (Evening Shift)

Molality of 0.8 M H2SO4 solution (density 1.06 g cm-3) is 10-3 m.

Answer

815

Solution

Take 1 L solution: mass = 1000 × 1.06 = 1060 g

Solute = 0.8 mol × 98 = 78.4 g ⇒ solvent = 1060 − 78.4 = 981.6 g

∴ m = 0.80.9816 = 0.815 m = 815 × 10-3 m

Answer: 815

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Ques. 2JEE Main 2024, 27 January (Morning Shift)

A solution of two miscible liquids showing negative deviation from Raoult's law will have :

  1. increased vapour pressure, increased boiling point
  2. increased vapour pressure, decreased boiling point
  3. decreased vapour pressure, decreased boiling point
  4. decreased vapour pressure, increased boiling point
Ques. 3JEE Main 2024, 27 January (Evening Shift)

The quantity which changes with temperature is :

  1. Molality
  2. Molarity
  3. Mole fraction
  4. Mass percentage

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