1
In an acidic medium, 10 mL of 0.25 M oxalic acid is titrated with KMnO4 solution. If the volume of KMnO4 solution required to reach end point is 10 mL, the strength of the KMnO4 solution is
- 0.15 M
- 0.10 M
- 0.20 M
- 0.25 M
Answer
(2) 0.10 M
Solution
In acidic medium, the redox half-reactions are:
MnO4- + 5e- + 8H+ Mn2+ + 4H2O (n1 = 5)
C2O42- 2CO2 + 2e- (n2 = 2)
Equating gram equivalents at the equivalence point:
N1 V1 = N2 V2
(MKMnO4 5) 10 = (0.25 2) 10
5 MKMnO4 = 0.50
MKMnO4 = 0.10 M
Answer: (2)
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