Let A be the point of intersection of the lines 3x+2y=14, 5x-y=6 and B be the point of intersection of the lines 4x+3y=8, 6x+y=5. The distance of the point P(5,-2) from the line AB is
- 132
- 8
- 52
- 6
Answer
(4) 6
Solution
5x-y=6 y=5x-6; put in 3x+2y=14: 13x=26 A(2,4)
6x+y=5 y=5-6x; put in 4x+3y=8: -14x=-7 B ( 12,2 )
Slope of AB = 4-22- 12= 43
AB: y-4= 43(x-2) 4x-3y+4=0
∵ distance = |ax1+by1+c| a2+b2
d= |4(5)-3(-2)+4| 16+9= 305=6
Answer: (4)