The position of the image formed by the combination of lenses is : [figure]
- 15 cm (right of second lens)
- 30 cm (right of third lens)
- 30 cm (left of third lens)
- 15 cm (left of second lens)
Answer
(2) 30 cm (right of third lens)
Solution
Lens formula 1v - 1u = 1f, lens by lens:
Lens 1: 1v1 = 110 + 1-30 = 115 v1 = 15 cm, i.e. 10 cm beyond lens 2
Lens 2: virtual object, u2 = +10 cm ⇒ 1v2 = 1-10 + 110 = 0 v2 =
the object of lens 2 is at its focus, the rays leave it parallel to the axis ⇒ lens 3 brings them to its focus
[figure]
image is f3 = 30 cm to the right of the third lens
Answer: (2)