A light ray is incident on a glass slab of thickness 4 3 cm and refractive index 2. The angle of incidence is equal to the critical angle for the glass slab with air. The lateral displacement of ray after passing through glass slab is cm. (Given 15 = 0.25)
Answer
2
Solution
d = t (i - r) r
i = C = 1 2 i = 45
Snell's law: 1 45 = 2 r r = 12 r = 30
d = 4 3 15 30 = 4 3 0.25 3/2
= 2 cm
Answer: 2