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Relations and Functions (Class 12) · Question 31

JEE Main 2025 (Online) 2nd April Morning ShiftMCQMedium📈 Topic in 45% papers+4−1
1

Let A be the set of all functions f : Z Z and R be a relation on A such that R = \(f, g) : f(0) = g(1) and f(1) = g(0)\. Then R is :

  1. Symmetric and transitive but not reflexive
  2. Symmetric but neither reflexive nor transitive
  3. Transitive but neither reflexive nor symmetric
  4. Reflexive but neither symmetric nor transitive

Answer

(2) Symmetric but neither reflexive nor transitive

Solution

Reflexive: (f, f) R needs f(0) = f(1), which fails for f(x) = x.

R is not reflexive.

Symmetric: (f, g) R f(0) = g(1), f(1) = g(0)

g(0) = f(1), g(1) = f(0) (g, f) R

R is symmetric.

Transitive: take f(x) = x + 1 and g(x) = 2 - x.

f(0) = 1 = g(1) and f(1) = 2 = g(0) (f, g) R; by symmetry (g, f) R.

But (f, f) R since f(0) = 1 2 = f(1).

R is not transitive.

Answer: (2)

JEE Main 2025 (Online) 2nd April Morning Shift

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2

Define a relation R on the interval [0, 2 ) by x R y if and only if 2 x - 2 y = 1. Then R is :

  1. both reflexive and symmetric but not transitive
  2. both reflexive and transitive but not symmetric
  3. reflexive but neither symmetric nor transitive
  4. an equivalence relation
JEE Main 2025 (Online) 29th January Morning Shift
3

If f(x) = 2x2x + 2, x R, then k=181 f ( k82 ) is equal to

  1. 82
  2. 81 2
  3. 41
  4. 812
JEE Main 2025 (Online) 28th January Morning Shift
4

The relation R = \(x, y) : x, y Z and x + y is even\ is:

  1. reflexive and transitive but not symmetric
  2. reflexive and symmetric but not transitive
  3. an equivalence relation
  4. symmetric and transitive but not reflexive
JEE Main 2025 (Online) 28th January Morning Shift
5

Let f: R - \0\ (- , 1) be a polynomial of degree 2, satisfying f(x)f ( 1x ) = f(x) + f ( 1x ). If f(K) = -2K, then the sum of squares of all possible values of K is:

  1. 9
  2. 1
  3. 6
  4. 7
JEE Main 2025 (Online) 28th January Evening Shift
6

Let f : [0, 3] A be defined by f(x) = 2x3 - 15x2 + 36x + 7 and g : [0, ) B be defined by g(x) = x2025x2025 + 1. If both the functions are onto and S = \x Z; x A or x B\, then n(S) is equal to :

  1. 29
  2. 31
  3. 30
  4. 36
JEE Main 2025 (Online) 28th January Evening Shift

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