An object of mass 100 kg falls from point A to B as shown in figure. The change in its weight, corrected to the nearest integer is (RE is the radius of the earth) [figure]
- 49 N
- 89 N
- 5 N
- 10 N
Answer
(1) 49 N
Solution
gh = g (1 + hRE )2
At A: hA = 2RE gA = g9
At B: hB = 2RE - RE2 = 3RE2 gB = g(5/2)2 = 4g25
Change in weight:
W = mg ( 425 - 19 )
= 100 10 36 - 25225
= 11000225 48.9 N 49 N
Answer: (1)