Gravitation · Question 11

A body of mass 60 g experiences a gravitational force of 3.0 N, when placed at a particular point. The magnitude of the gravitational field intensity at that point is

1. 0.05 N/kg
2. 50 N/kg
3. 20 N/kg
4. 180 N/kg

Match List - I with List - II Choose the correct answer from the options given below

1. (a)-(ii), (b)-(i), (c)-(iv), (d)-(iii)
2. (a)-(ii), (b)-(iv), (c)-(i), (d)-(iii)
3. (a)-(ii), (b)-(iv), (c)-(iii), (d)-(i)
4. (a)-(iv), (b)-(ii), (c)-(i), (d)-(iii)

A gravitational field is present in a region and a mass is shifted from A to B through different paths as shown. If W1, W2 and W3 represent the work done by the gravitational force along the respective paths, then : [figure]

1. W1 < W2 < W3
2. W1 = W2 = W3
3. W1 > W2 > W3
4. W1 > W3 > W2

In a gravitational field, the gravitational potential is given by, V = - Kx (J/Kg). The gravitational field intensity at point (2, 0, 3) m is

1. + K4
2. + K2
3. - K2
4. - K4

The escape velocity from the Earth's surface is v. The escape velocity from the surface of another planet having a radius, four times that of Earth and same mass density is :

1. 4v
2. v
3. 2v
4. 3v

A particle of mass 'm' is projected with a velocity v = kVe (k < 1) from the surface of the earth. (Ve = escape velocity) The maximum height above the surface reached by the particle is :

1. Rk21-k2
2. R ( k1-k2 )2
3. R ( k1+k2 )2
4. R2k1+k

A body weighs 72 N on the surface of the earth. What is the gravitational force on it, at a height equal to half the radius of the earth?

1. 32 N
2. 30 N
3. 24 N
4. 48 N

The work done to raise a mass m from the surface of the earth to a height h, which is equal to the radius of the earth, is :

1. mgR
2. 2mgR
3. 12mgR
4. 32mgR

A body weighs 200 N on the surface of earth. How much will it weigh half way down to the centre of the earth?

1. 200 N
2. 250 N
3. 100 N
4. 150 N

The kinetic energies of a planet in an elliptical orbit about the Sun, at positions A, B and C are KA, KB and KC, respectively. AC is the major axis and SB is perpendicular to AC at the position of the Sun S as shown in the figure. Then [figure]

1. KA < KB < KC
2. KA > KB > KC
3. KB < KA < KC
4. KB > KA > KC