During " S " estimation, 160 mg of an organic compound gives 466 mg of barium sulphate. The percentage of Sulphur in the given compound is %. (Given molar mass in g mol-1 of Ba : 137, S : 32, O : 16)
Answer
40
Solution
Concept: Carius method: all S ends up as BaSO4 (233 g mol-1).
\% S= 32233 466160 100, and 466=2 233
\% S= 32 2160 100=40
Answer: 40