PYQSidePowered byPrepblink ExamsMy practice

Integrals

JEE Main 2024 (Online) 9th April Evening ShiftMCQMedium📈 Topic in 24% papers+4−1
Ques. 1JEE Main 2024, 9 April (Evening Shift)

The integral 1/43/4 (2 -1 1 - x1 + x ) dx is equal to

  1. -1/2
  2. -1/4
  3. 1/4
  4. 1/2

Answer

(2) -1/4

Solution

Let = -1 1 - x1 + x; then = 1 + x1 - x, since > 0.

Using 2 = 1 - 2 1 + 2 , the integrand becomes

2 = 1 - 1 + x1 - x1 + 1 + x1 - x = (1 - x) - (1 + x)(1 - x) + (1 + x) = -x

I = 1/43/4 (-x) dx = - [ x22 ]1/43/4

= - 12 ( 916 - 116 ) = - 14

Answer: (2)

Keep practising — Integrals

Ques. 2JEE Main 2024, 9 April (Evening Shift)

x 2 ( x3( /2)3 ( (2t1/3 ) + (t1/3 ) ) dt (x - 2 )2 ) is equal to

  1. 3 22
  2. 9 28
  3. 5 29
  4. 11 210
Ques. 3JEE Main 2024, 9 April (Evening Shift)

The value of the integral -12 e (x + x2 + 1 ) dx is

  1. 5 - 2 + e ( 7 + 4 51 + 2 )
  2. 2 - 5 + e ( 7 + 4 51 + 2 )
  3. 5 - 2 + e ( 9 + 4 51 + 2 )
  4. 2 - 5 + e ( 9 + 4 51 + 2 )
Ques. 4JEE Main 2024, 8 April (Morning Shift)

The value of k N for which the integral In = 01 (1 - xk )n dx, n N, satisfies 147 I20 = 148 I21 is

  1. 8
  2. 14
  3. 7
  4. 10
Ques. 5JEE Main 2024, 8 April (Morning Shift)

Let I(x) = 6 2 x(1 - x)2 dx. If I(0) = 3, then I ( 12 ) is equal to

  1. 3
  2. 2 3
  3. 6 3
  4. 3 3
Ques. 6JEE Main 2024, 8 April (Evening Shift)

Let e 4 dx ex - 1 = 6. Then e and e- are the roots of the equation :

  1. 2x2 - 5x + 2 = 0
  2. x2 - 2x - 8 = 0
  3. 2x2 - 5x - 2 = 0
  4. x2 + 2x - 8 = 0
Ques. 7JEE Main 2024, 8 April (Evening Shift)

If 1 [5](x - 1)4(x + 3)6 dx = A ( x - 1 x + 3 )B + C, where C is the constant of integration, then the value of + + 20AB is .

Ques. 8JEE Main 2024, 6 April (Morning Shift)

0 /4 2 x 2 x ( 3 x + 3 x )2dx is equal to

  1. 1/9
  2. 1/6
  3. 1/3
  4. 1/12
Ques. 9JEE Main 2024, 6 April (Morning Shift)

Let rk = 01 (1 - x7 )k dx 01 (1 - x7 )k+1 dx, k N. Then the value of k=110 17 (rk - 1 ) is equal to .

Ques. 10JEE Main 2024, 6 April (Evening Shift)

If 1a2 2 x + b2 2 x dx = 112 -1(3 x) + constant, then the maximum value of a x + b x, is :

  1. 41
  2. 39
  3. 40
  4. 42
Ques. 11JEE Main 2024, 6 April (Evening Shift)

Let [t] denote the largest integer less than or equal to t. If 03 ( [x2 ] + [ x22 ] )dx = a + b 2 - 3 - 5 + c 6 - 7, where a, b, c Z, then a + b + c is equal to .

All Integrals PYQs →

PDFDownload Integrals PYQs as PDF Free, with answer key and a QR code to every solution — print it or study offline⬇
All JEE Main Mathematics chapters