In an a.c. circuit the e.m.f. ( ) and the current (i) at any instant are given respectively by = E0 sin t, i = I0 sin( t - ) The average power in the circuit over one cycle of a.c. is
- E0I02
- E0I0
- E0I02
- E0I02
Answer
(1) E0I02
Solution
Pav = rms Irms
= E0 2 I0 2
= E0I02
Answer: (1)