Power dissipated in an LCR series circuit connected to an A.C. source of emf is
- 2 [R2 + (L - 1C )2 ]R
- 2 R2 + (L - 1C )2R
- 2 R R2 + (L - 1C )2
- 2 R [R2 + (L - 1C )2 ]
Answer
(4) 2 R [R2 + (L - 1C )2 ]
Solution
Impedance: Z = R2 + (L - 1C )2
Current (rms): I = Z
Power is dissipated only in the resistor:
P = I2 R = 2 RZ2
P = 2 R [R2 + (L - 1C )2 ]
Answer: (4)