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Electromagnetic Waves · Question 10

JEE Main 2026 (Online) 24th January Morning ShiftMatchingEasy📈 Topic in 3% papers+4−1
1

Match the LIST-I with LIST-II Choose the correct answer from the options given below:

  1. A-IV, B-II, C-I, D-III
  2. A-IV, B-III, C-I, D-II
  3. A-IV, B-I, C-II, D-III
  4. A-II, B-IV, C-III, D-I

Answer

(3) A-IV, B-I, C-II, D-III

Solution

A. Radio waves are produced by the rapid acceleration of electrons in conducting wires (aerials) IV

B. Microwaves are produced by special vacuum tubes such as the magnetron valve I

C. Infrared waves are produced by hot bodies and molecules; they arise from changes in the vibrational modes of atoms and molecules II

D. X-rays are produced when inner shell electrons move from a higher energy level to a lower energy level III

A-IV, B-I, C-II, D-III

Answer: (3)

JEE Main 2026 (Online) 24th January Morning Shift

Keep practising — Electromagnetic Waves

2

A point source is kept at the center of a spherically enclosed detector. If the volume of the detector is increased by 8 times, the intensity will

  1. increase by 64 times
  2. decrease by 4 times
  3. decrease by 8 times
  4. increase by 8 times
JEE Main 2026 (Online) 24th January Evening Shift
3

Match List-I with List-II. Choose the correct answer from the options given below :

  1. A-I, B-IV, C-III, D-II
  2. A-II, B-III, C-IV, D-I
  3. A-IV, B-I, C-II, D-III
  4. A-II, B-III, C-I, D-IV
JEE Main 2026 (Online) 23rd January Morning Shift
4

The equation of the electric field of an electromagnetic wave propagating through free space is given by : E = 377 (6.27 103 t - 2.09 10-5 x) N/C The average intensity of the electromagnetic wave is ( 1 ) W/m2. The value of α is . (Take 0 0 = 377 in SI units )

JEE Main 2026 (Online) 23rd January Morning Shift
5

The ratio of speeds of electromagnetic waves in vacuum and a medium, having dielectric constant k = 3 and permeability of = 2 0, is ( 0 = permeability of vacuum)

  1. 6 : 1
  2. 3 : 2
  3. 6 : 1
  4. 36 : 1
JEE Main 2026 (Online) 23rd January Evening Shift
6

The electric field of a plane electromagnetic wave, travelling in an unknown nonmagnetic medium is given by, Ey = 20 (3 106 x - 4.5 1014 t ) V/m (where x, t and other values have S.I. units). The dielectric constant of the medium is (speed of light in free space is 3 108 m/s)

JEE Main 2026 (Online) 22nd January Morning Shift
7

A laser beam has intensity of 4.0 1014 W/m2. The amplitude of magnetic field associated with beam is T. (Take 0 = 8.85 10-12 C2/Nm2 and c = 3 108 m/s)

  1. 1.83
  2. 2.0
  3. 5.5
  4. 18.3
JEE Main 2026 (Online) 22nd January Evening Shift
8

If , E and t represent the free space permittivity, electric field and time respectively, then the unit of Et will be :

  1. Am
  2. A/m
  3. A/m2
  4. Am2
JEE Main 2026 (Online) 22nd January Evening Shift
9

The electric field in a plane electromagnetic wave is given by : Ey = 69 [0.6 103x - 1.8 1011t ] V/m. The expression for magnetic field associated with this electromagnetic wave is T.

  1. Bz = 2.3 10-7 [0.6 103x - 1.8 1011t ]
  2. Bz = 2.3 10-7 [0.6 103x + 1.8 1011t ]
  3. By = 2.3 10-7 [0.6 103x - 1.8 1011t ]
  4. By = 69 [0.6 103x + 1.8 1011t ]
JEE Main 2026 (Online) 21st January Morning Shift
10

An electromagnetic wave of frequency 100 MHz propagates through a medium of conductivity, = 10 mho/m. The ratio of maximum conduction current density to maximum displacement current density is . [Take 14 0 = 9 109 N m2/C2]

JEE Main 2026 (Online) 21st January Evening Shift
11

If 0 denotes the permittivity of free space and E is the flux of the electric field through the area bounded by the closed surface, then dimensions of ( 0 d Edt ) are that of :

  1. electric charge
  2. electric field
  3. electric current
  4. electric potential
JEE Main 2025 (Online) 7th April Morning Shift

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