Electromagnetic Waves · Question 9

Match the LIST-I with LIST-II Choose the correct answer from the options given below:

1. A-IV, B-II, C-I, D-III
2. A-IV, B-III, C-I, D-II
3. A-IV, B-I, C-II, D-III
4. A-II, B-IV, C-III, D-I

A point source is kept at the center of a spherically enclosed detector. If the volume of the detector is increased by 8 times, the intensity will

1. increase by 64 times
2. decrease by 4 times
3. decrease by 8 times
4. increase by 8 times

Match List-I with List-II. Choose the correct answer from the options given below :

1. A-I, B-IV, C-III, D-II
2. A-II, B-III, C-IV, D-I
3. A-IV, B-I, C-II, D-III
4. A-II, B-III, C-I, D-IV

The equation of the electric field of an electromagnetic wave propagating through free space is given by : E = 377 (6.27 103 t - 2.09 10-5 x) N/C The average intensity of the electromagnetic wave is ( 1 ) W/m2. The value of α is . (Take 0 0 = 377 in SI units )

The ratio of speeds of electromagnetic waves in vacuum and a medium, having dielectric constant k = 3 and permeability of = 2 0, is ( 0 = permeability of vacuum)

1. 6 : 1
2. 3 : 2
3. 6 : 1
4. 36 : 1

The electric field of a plane electromagnetic wave, travelling in an unknown nonmagnetic medium is given by, Ey = 20 (3 106 x - 4.5 1014 t ) V/m (where x, t and other values have S.I. units). The dielectric constant of the medium is (speed of light in free space is 3 108 m/s)

A laser beam has intensity of 4.0 1014 W/m2. The amplitude of magnetic field associated with beam is T. (Take 0 = 8.85 10-12 C2/Nm2 and c = 3 108 m/s)

1. 1.83
2. 2.0
3. 5.5
4. 18.3

If , E and t represent the free space permittivity, electric field and time respectively, then the unit of Et will be :

1. Am
2. A/m
3. A/m2
4. Am2

The electric field in a plane electromagnetic wave is given by : Ey = 69 [0.6 103x - 1.8 1011t ] V/m. The expression for magnetic field associated with this electromagnetic wave is T.

1. Bz = 2.3 10-7 [0.6 103x - 1.8 1011t ]
2. Bz = 2.3 10-7 [0.6 103x + 1.8 1011t ]
3. By = 2.3 10-7 [0.6 103x - 1.8 1011t ]
4. By = 69 [0.6 103x + 1.8 1011t ]

An electromagnetic wave of frequency 100 MHz propagates through a medium of conductivity, = 10 mho/m. The ratio of maximum conduction current density to maximum displacement current density is . [Take 14 0 = 9 109 N m2/C2]