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Binomial Theorem · Question 29

JEE Main 2025 (Online) 2nd April Morning ShiftMCQMedium📈 Topic in 23% papers+4−1
1

The term independent of x in the expansion of ( (x + 1)(x2/3 + 1 - x1/3) - (x - 1)(x - x1/2) )10, x > 1, is :

  1. 240
  2. 120
  3. 150
  4. 210

Answer

(4) 210

Solution

x + 1 = (x1/3 + 1)(x2/3 - x1/3 + 1) x + 1x2/3 + 1 - x1/3 = x1/3 + 1

x - 1x - x1/2 = ( x - 1)( x + 1) x( x - 1) = 1 + x-1/2

Expression = (x1/3 - x-1/2 )10

Tr+1 = 10Cr (x1/3)10 - r(-x-1/2)r

Power of x: 10 - r3 - r2 = 0 20 - 5r = 0 r = 4

T5 = 10C4 (-1)4 = 210

Answer: (4)

JEE Main 2025 (Online) 2nd April Morning Shift

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2

If r=010 ( 10r+1 - 110r ) 11Cr+1 = 11 - 11111010, then is equal to :

  1. 11
  2. 20
  3. 24
  4. 15
JEE Main 2025 (Online) 2nd April Evening Shift
3

The least value of n for which the number of integral terms in the Binomial expansion of ( [3]7 + [12]11)n is 183, is :

  1. 2184
  2. 2172
  3. 2196
  4. 2148
JEE Main 2025 (Online) 29th January Morning Shift
4

If = 1 + r=16(-3)r-1 12C2r-1, then the distance of the point (12, 3) from the line x - 3y + 1 = 0 is .

JEE Main 2025 (Online) 28th January Morning Shift
5

Let the coefficients of three consecutive terms Tr, Tr+1 and Tr+2 in the binomial expansion of (a + b)12 be in a G.P. and let p be the number of all possible values of r. Let q be the sum of all rational terms in the binomial expansion of ( [4]3 + [3]4)12. Then p + q is equal to:

  1. 295
  2. 283
  3. 299
  4. 287
JEE Main 2025 (Online) 28th January Evening Shift

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