In a Young's double slit experiment, two slits are located 1.5 mm apart. The distance of screen from slits is 2 m and the wavelength of the source is 400 nm. If the 20 maxima of the double slit pattern are contained within the central maximum of the single slit diffraction pattern, then the width of each slit is x 10-3 cm, where x-value is .
Answer
15
Solution
Fringe width of the double slit pattern: = Dd
Width of the central maximum of the single slit pattern (slit width a): W = 2 Da
20 maxima lie within the central maximum:
2 Da = 20 Dd
a = d10 = 1.5 mm10 = 0.15 mm
a = 0.015 cm = 15 10-3 cm
x = 15
Answer: 15