A thin transparent film with refractive index 1.4, is held on circular ring of radius 1.8 cm. The fluid in the film evaporates such that transmission through the film at wavelength 560 nm goes to a minimum every 12 seconds. Assuming that the film is flat on its two sides, the rate of evaporation is 10-13 m3/s.
Answer
54
Solution
Thin film in air (normal incidence), transmitted light is minimum when 2 d = (m + 12 ) (d = thickness)
Between two successive minima the thickness decreases by
d = 2 = 560 10-92 1.4 = 2 10-7 m
Volume evaporated in 12 s:
V = r2 d = (1.8 10-2)2 2 10-7 = 6.48 10-11 m3
Rate of evaporation: V12 = 0.54 10-11 = 54 10-13 m3/s
Answer: 54