PYQSide ExamsMy practice

Complex Numbers and Quadratic Equations · Question 36

JEE Main 2026 (Online) 21st January Evening ShiftMCQMedium📈 Topic in 45% papers+4−1
1

Let z be the complex number satisfying |z - 5| 3 and having maximum positive principal argument. Then 34 | 5z - 125iz + 16 |2 is equal to:

  1. 20
  2. 26
  3. 12
  4. 16

Answer

(1) 20

Solution

|z - 5| 3 is the disc with centre (5, 0) and radius 3

Maximum argument at the point where the tangent from O touches the circle

Tangent length = 52 - 32 = 4; = 35, = 45

z = 4( + i ) = 16 + 12i5

5z - 12 = 4 + 12i

5iz + 16 = i(16 + 12i) + 16 = 4 + 16i

| 5z - 125iz + 16 |2 = 16 + 14416 + 256 = 160272 = 1017

34 1017 = 20

Answer: (1)

JEE Main 2026 (Online) 21st January Evening Shift

Keep practising — Complex Numbers and Quadratic Equations

2

Let be a solution of x2 + x + 1 = 0, and for some a and b in R, bmatrix 4 & a & b bmatrix bmatrix 1 & 16 & 13 \ -1 & -1 & 2 \ -2 & -14 & -8 bmatrix = bmatrix 0 & 0 & 0 bmatrix. If 4 4 + m a + n b = 3, then m + n is equal to

  1. 11
  2. 3
  3. 8
  4. 7
JEE Main 2025 (Online) 8th April Evening Shift
3

The sum of the squares of the roots of |x-2|2 + |x-2| - 2 = 0 and the squares of the roots of x2 - 2|x-3| - 5 = 0, is

  1. 24
  2. 26
  3. 36
  4. 30
JEE Main 2025 (Online) 8th April Evening Shift
4

Let A = \ [0, 2 ] : 1 + 10 Re ( 2 + i - 3i ) = 0 \. Then A 2 is equal to

  1. 214 2
  2. 6 2
  3. 274 2
  4. 8 2
JEE Main 2025 (Online) 8th April Evening Shift
5

Let the set of all values of p R, for which both the roots of the equation x2 - (p + 2)x + (2p + 9) = 0 are negative real numbers, be the interval ( , ]. Then - 2 is equal to

  1. 5
  2. 0
  3. 20
  4. 9
JEE Main 2025 (Online) 7th April Morning Shift
6

Among the statements (S1) : The set \z C - \-i\ : |z| = 1 and z - iz + i is purely real \ contains exactly two elements, and (S2) : The set \z C - \-1\ : |z| = 1 and z - 1z + 1 is purely imaginary \ contains infinitely many elements.

  1. both are incorrect
  2. both are correct
  3. only (S2) is correct
  4. only (S1) is correct
JEE Main 2025 (Online) 7th April Morning Shift
7

If the locus of z C, such that Re ( z-12z+i ) + Re ( z-12 z-i ) = 2, is a circle of radius r and center (a, b), then 15abr2 is equal to :

  1. 16
  2. 24
  3. 12
  4. 18
JEE Main 2025 (Online) 7th April Evening Shift
8

The number of real roots of the equation x|x-2| + 3|x-3| + 1 = 0 is :

  1. 4
  2. 3
  3. 2
  4. 1
JEE Main 2025 (Online) 7th April Evening Shift
9

For t > -1, let t and t be the roots of the equation ((t + 2)1/7 - 1 )x2 + ((t + 2)1/6 - 1 )x + ((t + 2)1/21 - 1 ) = 0 If t -1+ t = a and t -1+ t = b, then 72(a + b)2 is equal to .

JEE Main 2025 (Online) 7th April Evening Shift
10

Consider the equation x2 + 4x - n = 0, where n [20, 100] is a natural number. Then the number of all distinct values of n, for which the given equation has integral roots, is equal to

  1. 6
  2. 5
  3. 8
  4. 7
JEE Main 2025 (Online) 4th April Morning Shift
11

Let A = \z C : |z - 2 - i| = 3\, B = \z C : Re(z - iz) = 2\ and S = A B. Then z S |z|2 is equal to .

JEE Main 2025 (Online) 4th April Morning Shift

All Complex Numbers and Quadratic Equations PYQs →

PDFDownload Complex Numbers and Quadratic Equations PYQs as PDF Free, with answer key and a QR code to every solution — print it or study offline⬇
All JEE Main Mathematics chapters