In a double slit experiment, when light of wavelength 400 nm was used, the angular width of the first minima formed on a screen placed 1 m away, was found to be 0.2°. What will be the angular width of the first minima, ( water = 4/3) if the entire experimental apparatus is immersed in water?
- 0.15°
- 0.05°
- 0.1°
- 0.266°
Answer
(1) 0.15°
Solution
Angular width of a fringe in the double slit experiment: = d
In water the wavelength becomes ' =
' =
= 0.2 4/3
= 0.15
Answer: (1)