The intensity at the maximum in a Young's double slit experiment is I0. Distance between two slits is d = 5 , where is the wavelength of light used in the experiment. What will be the intensity in front of one of the slits on the screen placed at a distance D = 10d?
- 34I0
- I02
- I0
- I04
Answer
(2) I02
Solution
Point in front of one slit: y = d2
Path difference: x = ydD = d2 d10d = d20
x = 5 20 = 4
Phase difference: = 2 4 = 2
I = I0 2 2 = I0 2 4
= I02
Answer: (2)