The temperature of a gas is -78 and the average translational kinetic energy of its molecules is K. The temperature at which the average translational kinetic energy of the molecules of the same gas becomes 2 K is :
- -78
- 127
- -39
- 117
Answer
(4) 117
Solution
Average translational KE = 32kBT, so KE T (in kelvin).
T1 = -78 + 273 = 195 K
KE doubles, so T2 = 2T1 = 390 K
T2 = 390 - 273 = 117
Answer: (4)