A mixture of one mole of monoatomic gas and one mole of a diatomic gas (rigid) are kept at room temperature (27 ). The ratio of specific heat of gases at constant volume respectively is:
- 32
- 35
- 75
- 53
Answer
(2) 35
Solution
CV = f2R (molar)
Monoatomic: f = 3 ⇒ CV = 32R
Rigid diatomic: f = 5 ⇒ CV = 52R
ratio = 3/25/2 = 35
Answer: (2)