A particle is executing simple harmonic motion. Its amplitude is A and time period is 5 sec. The time required by it to move from x=A to x= A 2 is sec.
- 1/4
- 5/4
- 5/8
- 3/8
Answer
(3) 5/8
Solution
Starting from the extreme position x=A:
x=A t
A 2=A t ⇒ t= 4
⇒ t= /42 /T= T8
∴ t= 58 s
Answer: (3)