A spring of force constant 15 N/m is cut into two pieces. If the ratio of their lengths is 1 : 3, then the force constant of smaller piece is N/m.
- 20
- 45
- 60
- 15
Answer
(3) 60
Solution
For a spring, k 1l, i.e. kl = constant.
Lengths of the pieces: l4 and 3l4
Smaller piece: k1 l4 = 15 l
k1 = 4 15 = 60 N/m
Answer: (3)