The area of the region, inside the circle (x-2 3)2+y2=12 and outside the parabola y2=2 3 x is :
- 3 -8
- 6 -8
- 3 +8
- 6 -16
Answer
(4) 6 -16
Solution
The circle and the parabola meet at (0,0) and (2 3, 2 3); the shaded part is the required area.
[figure]
By symmetry, area =2 02 3 [ 12-(x-2 3)2- 2 3 x ]dx
Circle part = quarter circle =3 ; parabola part = 23(2 3)2=8
area =2(3 -8)=6 -16
Answer: (4)