Let P(3,2,3), Q(4,6,2) and R(7,3,2) be the vertices of . Then, the angle is
- -1 ( 718 )
- 6
- -1 ( 118 )
- 3
Answer
(4) 3
Solution
[figure]
PQ=(1,4,-1), PR=(4,1,-1), QR=(3,-3,0)
=PR=QR= 18 (equilateral triangle)
∵ = PQ PRPQ = 4+4+118= 12
= 3
Answer: (4)
Let P(3,2,3), Q(4,6,2) and R(7,3,2) be the vertices of . Then, the angle is
(4) 3
[figure]
PQ=(1,4,-1), PR=(4,1,-1), QR=(3,-3,0)
=PR=QR= 18 (equilateral triangle)
∵ = PQ PRPQ = 4+4+118= 12
= 3
Answer: (4)
Let O be the origin, and M and N be the points on the lines x-54= y-41= z-53 and x+812= y+25= z+119 respectively such that MN is the shortest distance between the given lines. Then OM ON is equal to .
The distance of the point (7,-2,11) from the line x-61= y-40= z-83 along the line x-52= y-1-3= z-56, is :
If the shortest distance between the lines x-41= y+12= z-3 and x- 2= y+14= z-2-5 is 6 5, then the sum of all possible values of is :
Let the position vectors of the vertices A, B and C of a triangle be 2 i+2 j+ k, i+2 j+2 k and 2 i+ j+2 k respectively. Let l1, l2 and l3 be the lengths of perpendiculars drawn from the orthocentre of the triangle on the sides AB, BC and CA respectively, then l12+l22+l32 equals:
Let the image of the point (1,0,7) in the line x1= y-12= z-23 be the point ( , , ). Then which one of the following points lies on the line passing through ( , , ) and making angles 2 3 and 3 4 with y-axis and z-axis respectively and an acute angle with x-axis ?
The lines x-22= y-2= z-716 and x+34= y+23= z+21 intersect at the point P. If the distance of P from the line x+12= y-13= z-11 is l, then 14l2 is equal to .